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Invariance of domain is a theorem in topology about homeomorphic subsets of Euclidean space R''n''. It states: :If ''U'' is an open subset of R''n'' and ''f'' : ''U'' → R''n'' is an injective continuous map, then ''V'' = ''f''(''U'') is open and ''f'' is a homeomorphism between ''U'' and ''V''. The theorem and its proof are due to L. E. J. Brouwer, published in 1912.〔 Beweis der Invarianz des ''n''-dimensionalen Gebiets, ''Mathematische Annalen'' 71 (1912), pages 305–315; see also 72 (1912), pages 55–56〕 The proof uses tools of algebraic topology, notably the Brouwer fixed point theorem. == Notes == The conclusion of the theorem can equivalently be formulated as: "''f'' is an open map". Normally, to check that ''f'' is a homeomorphism, one would have to verify that both ''f'' and its inverse function ''f'' −1 are continuous; the theorem says that if the domain is an ''open'' subset of R''n'' and the image is also in R''n'', then continuity of ''f'' −1 is automatic. Furthermore, the theorem says that if two subsets ''U'' and ''V'' of R''n'' are homeomorphic, and ''U'' is open, then ''V'' must be open as well. (Note that V is open as a subset of R''n'', and not just in the subspace topology. Openness of V in the subspace topology is automatic. ) Both of these statements are not at all obvious and are not generally true if one leaves Euclidean space. It is of crucial importance that both domain and range of ''f'' are contained in Euclidean space ''of the same dimension''. Consider for instance the map ''f'' : (0,1) → R2 with ''f''(''t'') = (''t'',0). This map is injective and continuous, the domain is an open subset of R, but the image is not open in R2. A more extreme example is ''g'' : (−1.1,1) → R2 with ''g''(''t'') = (''t'' 2 − 1, ''t'' 3 − ''t'') because here ''g'' is injective and continuous but does not even yield a homeomorphism onto its image. The theorem is also not generally true in infinite dimensions. Consider for instance the Banach space ''l''∞ of all bounded real sequences. Define ''f'' : ''l''∞ → ''l''∞ as the shift ''f''(''x''1,''x''2,...) = (0, ''x''1, ''x''2,...). Then ''f'' is injective and continuous, the domain is open in ''l''∞, but the image is not. 抄文引用元・出典: フリー百科事典『 ウィキペディア（Wikipedia）』 ■ウィキペディアで「invariance of domain」の詳細全文を読む スポンサード リンク
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